Botany
publish date: 2024/05/09 12:11:00 UTC
volume_muteTo determine the effects of smog on tree development, a scientist cut down a pine tree and measured the width of the growth rings for the last two years.
The measure of the first year was \(\frac{1}{16}\) in and the measure of the second year on top of the first year was \(\frac{5}{32}\) in
- What was the growth over this two-year period?
- What is the difference in the widths of the two rings?
Use "/" to write the fraction in your answer e.g. 1/2 or 3/4
Correct Answer
Explanation
What is given in this problem is the widths of the two rings
width 1 for the first year= \(\frac{1}{16}\)
width 2 from the last measure point tsken on the second year = \(\frac{5}{32}\)
Let's find the LCD first, which is 32
We can write the first width as = \(\frac{1}{16} \cdot 22 = \frac{2}{32}\)
- The growth over this two-year period can be found by adding both widths
- = \(\frac{5}{35} + \frac{2}{32} = \frac{7}{32}\)
- The difference in the widths of the two rings is
- = \(\frac{5}{32} - \frac{2}{32} = \frac{3}{32}\)
Reference
Mathematics for college students, go-math-science.com