Subtract the following

$22\frac{11}{24}$

Explanation

We will subtract the fractional parts and the whole number parts separately.

The LCD for \(\frac18\) and \(\frac23\) is 24

• build \(\frac18\) and \(\frac23\) so that their denominators are 24.
  • \(34 \frac18 \cdot \frac33 - 11 \frac23 \cdot \frac88\)
• Since \(\frac{16}{24}\) is greater than \(\frac{3}{24}\), borrow 1 (in the form of \(\frac{24}{24}\) from 34 and add it to \(\frac{3}{24}\) to get \(\frac{27}{24}\)
  • = \(\require{cancel} \cancel{34} \frac{3}{24} + \frac{24}{24} - 11\frac{16}{24}\)
• Subtract the fractions separately
  • = \(33\frac{27}{24} - 11 \frac{16}{24} = \frac{11}{24}\)
• Subtract the whole numbers separately
  • =\(33\frac{27}{24} - 11\frac{16}{24} = 22\frac{11}{24}\)

The difference is \(22\frac{11}{24}\)