Surfboard Designs
publish date: 2024/04/21 23:14:35.892803 UTC
Most surfboards are made of a foam core covered with several layers of fiberglass to keep them water-tight. How many layers are needed to build up a finish \(\frac38\) of an inch thick if each layer of fiberglass has a thickness of \(\frac{1}{16}\) of an inch?
Correct Answer
Explanation
Analyze
- The surfboard is to have a \(\frac38\)-inch-thick fiberglass finish (Given)
- Each layer of fiberglass is \(\frac{1}{16}\) of an inch thick. (Given)
- How many layers of fiberglass need to be applied? (Find)
Form
Think of the \(\frac38\)-inch-thick finish separated into an unknown number of equally thick layers of fiberglass. This indicates division. We translate the words of the problem to numbers and symbols
[The number of layers of fiberglass that are needed] is equal to [the thickness of the finish] divided by [the thickness of 1 layer of the fiberglass]
The number of layers of fiberglass that are needed = \(\frac38 ÷ \frac{1}{16}\)
Solve
To find the quotient, we will use the rule for dividing two fractions
- Multiply \(\frac38\) by the reciprocal of \(\frac{1}{16}\), which is \(\frac{16}{1}\)
- \(\frac38 \color{red}{÷ \frac{1}{16}} = \frac38 \color{red}{\cdot \frac{16}{1}}\)
- Multiply the numerators. Multiply the denominators
- = \(\frac{3 \cdot 16}{8 \cdot 1}\)
- To simplify, factor 16 as 2 • 8. Then remove the common factor of 8 from the numerator and denominator.
- = \(\require{cancel} \frac{3 \cdot 2 \cdot \cancel{8}^1}{\cancel{8}_1 \cdot 1}\)
- Multiply the remaining factors in the numerators. Multiply the remaining factors in the denominator.
- = \(\frac61\)
- Any whole number divided by 1 is the same number
- = 6
State The number of layers of fiberglass needed is 6
Check
If 6 layers of fiberglass, each \(\frac{1}{16}\) of an inch thick, are used, the finished thickness will be \(\frac{6}{16}\) of an inch. If we simplify \(\frac{6}{16}\), we see that it is equivalent to the desired finish thickness
$\require{cancel} \frac{6}{16} = \frac{\cancel{2}^1 \cdot 3}{\cancel{2}_1} \cdot 8 = \frac38$
The result checks
Reference
Mathematics for college students