Television channels
publish date: 2024/12/24 04:26:12.166315 UTC
volume_muteFind the percent increase in the number of television channels received by the average American home from 2000 to 2007?
Round the answer
Year | Number of television channels that the average U.S. home received |
2000 | 61 |
2007 | 119 |
Source: The Nielsen Company
Answer = %
Correct Answer
Explanation
From the table, we see that the number of television channels received increased considerably from 2000 to 2007.To describe this increase using a percent, we first subtract to find the amount of increase.
- Subtract the number of TB channels received in 2000 from the number received in 2007.
- 119 - 61 = 58
Thus, the number of channels received increased by 58 from 200 to 2007.
Next, we find what percent of the original 61 channels received in 200 that the 58 channel increase represent. To do this, we translate the problem into a percent equation (or percent proportion) and solve it.
The percent equation method:
58 is what percent of 61?
58 = x • 61
- This is the equation to solve.
- 58 = x • 61
- To isolate x on the right side, divide both sides of the equation by 61. Then remove the common factor of 61 from the numerator and denominator.
- \(\require{cancel} \frac{58}{61} = \frac{x \cdot \cancel{61}^1}{\cancel{61}_1}\)
- \(\frac{58}{61} = x\)
- On the left side of the equation, divide 58 by 61. The division does not terminate.
- 0.9508 ≈ x
- To write the decimal 0.9508 as a percent, multiply it by 100 by moving the decimal point two places to the right, and then insert a % symbol.
- 95.08% ≈ x
- Round to the nearest one percent
- 95% ≈ x
Reference
Mathematics for college students