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Onto (Surjective) Function — Identify From a Diagram
publish date: 2026/05/23 18:47:48.208461 UTC
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Study the diagram below.
Which property does this mapping demonstrate?
Correct Answer
Onto (surjective): every codomain element has at least one pre-image
Explanation
A function \(f: A \to B\) is onto (surjective) if every element of the codomain is the image of at least one domain element. Here: \(1\) ← \(a\), \(2\) ← \(b\) and \(c\), \(3\) ← \(d\) — every codomain element is hit. Note that \(2\) has two pre-images (\(b\) and \(c\)), so the function is not injective — but surjectivity only requires each codomain element to be hit at least once.
Reference
Introduction to Differential Calculus (Systematic Studies with Engineering Applications for Beginners) - 2012
