volume_mute

What mass of gold (Au) is required to

publish date2024/06/18 19:41:53.334439 UTC

have 1025 gold atoms?

volume_mute

Correct Answer

$3270$

Explanation

3270 grams

\(10^{25}\) molecules is \(\frac{10^25}{6.02 \cdot 10^{23}}\) or 16.6 mole

One mole of gold (atomic mass 197) has a mass of 197 grams, so we need 16.6 times this, or 3270 grams.

Reference

Basic Physics: A Self-Teaching Guide


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