The Law of Gravity

Every object in the universe attracts every other object in the universe with a 1($) proportional to the objects' 2($) and inversely proportional to the square of the 3($) between their centers.

$F \sim \frac{m_1 \cdot m_2}{d^2}$

1($) is the force of gravity between two objects

2($) means "is proportional to"

3($) is the mass of one of the objects

4($) is the distance between the centers of the objects

The Newton's law of gravity says that there is a force of gravity between every two objects, between you and the person next to you, and between you and a bus out on the street.

Why do not you feel the force between you and the computer or mobile you are using now?

In the Newton's Law of Gravity, the force changes 1($) as the 2($) of the distance

Suppose two objects are initially 5 meters apart and then are moved to 1 meter apart.  How does the force of gravity between them change?

Your distance to the center of the earth is about 4000 miles when I am on the surface.  If you go to a height of 4000 miles above the surface of the earth, the force of gravity (your weight) then becomes what fraction of your present weight?

How far from the center of the earth must you go to weigh 13 pounds?

Note: You distance to the center of the earth is about 4000 miles when you are on the surface

How far from the center of the earth must you go to weigh 13 pounds?

Note: You distance to the center of the earth is about 4000 miles when you are on the surface

As one rises above the surface of earth, does the acceleration of gravity become greater or less?

Does an object fall more or less far during the first second of fall if it is high above the earth compared to being at sea level?

Suppose an object is 60 times as far from earth-center as the earth's surface is from earth-center.  What fraction of 4.9 meters will the object fall in one second?

Suppose an object is 60 times as far from earth-center as the earth's surface is from earth-center.  What fraction of 4.9 meters will the object fall in one second?