volume_mute
Boyle's Law Application
publish date: 2026/05/20 22:35:54.275958 UTC
A certain gas occupies a volume of \(20\text{ cm}^3\) at a pressure of \(100\text{ kPa}\). If the volume is decreased to \(10\text{ cm}^3\) while keeping the temperature constant, what is the new pressure in kPa?
Answer = (1)
Correct Answer
(1) 200
Explanation
According to Boyle's Law (\(P_1V_1 = P_2V_2\)), pressure and volume are inversely proportional at a constant temperature. Reducing the volume to half (\(20\text{ cm}^3\) to \(10\text{ cm}^3\)) must double the pressure from \(100\text{ kPa}\) to \(200\text{ kPa}\).
Reference
Basic Physics: A Self-Teaching Guide