volume_mute
Calculating Displaced Fluid Weight
publish date: 2026/05/20 22:35:58.923822 UTC
An object with a total volume of \(3\text{ ft}^3\) is completely submerged in water (weight density = \(62.4\text{ lb/ft}^3\)). What is the magnitude of the upward buoyant force acting on this object, in pounds?
Answer = (1)
Correct Answer
(1) 187.2
Explanation
By Archimedes' principle, the buoyant force equals the weight of the displaced fluid:
\[ F_b = \text{Volume} \times \text{Weight Density} \]
\[ F_b = 3\text{ ft}^3 \times 62.4\text{ lb/ft}^3 = 187.2\text{ lb} \]
Reference
Basic Physics: A Self-Teaching Guide