volume_mute
Pressure Depth Calculations
publish date: 2026/05/20 22:35:55.642710 UTC
Water has a weight density of \(62.4\text{ lb/ft}^3\). Calculate the liquid pressure (excluding atmospheric pressure) at a depth of \(10\text{ feet}\) beneath the surface of a calm lake, in pounds per square foot.
Answer = (1)
Correct Answer
(1) 624
Explanation
The fluid pressure due to a liquid column is calculated by multiplying the weight density by the depth:
\[ P = \text{Weight Density} \times \text{Depth} \]
\[ P = 62.4\text{ lb/ft}^3 \times 10\text{ ft} = 624\text{ lb/ft}^2 \]
Reference
Basic Physics: A Self-Teaching Guide