volume_mute
What pressure would a 450-N (110-lb) woman exert on the floor when she puts her entire weight on one heel?
publish date: 2024/09/09 20:38:34.196564 UTC
volume_muteIn the 1950s, when women wore spike heels with areas of about \(\frac14\) cm2 (\(\frac12\) cm by \(\frac12\) cm), aircraft companies were concerned because such heels could exert enough pressure to punch through the floor of planes.
What pressure would a 450-N (110-lb) woman exert on the floor when she puts her entire weight on one heel?
Express your answer in N/cm2
Answer = N/cm2
Correct Answer
(1) 1800
Explanation
$\text{Pressure} = \frac{\text{450-N woman}}{\text{one heel area}}$
$\text{Pressure} = \frac{450 \text{ N}}{\frac14 \text{ cm}^2} = 450 \cdot 4 = 1800 \text{ N/cm}^2$
Reference
Basic Physics: A Self-Teaching Guide, go-math-science.com