Melting, Boiling, and the Heat Needed to Change State

Explore the heat of fusion and heat of vaporization, the difference between crystalline and amorphous solids, and how to calculate the total heat needed to carry a substance through several changes of state.

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Views #: 114
Questions #: 11
Time: 20 minutes
Pass Score: 80.0%
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The Heat of Fusion of Water

1 pts
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The amount of heat required to change 1 gram of ice at 0°C to 1 gram of water at 0°C is 80 calories. Is this statement true?

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Melting 10 Grams of Ice

1 pts
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The heat of fusion of water is 80 calories per gram. How many calories are needed to change 10 grams of ice at 0°C to 10 grams of water at 0°C?

Answer = (1)

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Melting 10 Grams of Lead

2 pts
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Lead's heat of fusion is 5.9 calories per gram — much lower than water's. How many calories are needed to change 10 grams of solid lead at its melting point to liquid lead at that same temperature?

Answer = (1)

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Is Margarine Crystalline or Amorphous?

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Margarine softens gradually as it warms rather than melting suddenly at one fixed temperature. Based on this behavior, is margarine best classified as a crystalline or an amorphous solid?

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Classify Solid Properties

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Examples
×Definite melting point
×Softens gradually when heated
×Bonds of varying strength
×Bonds of uniform strength
×Melts suddenly at a fixed temperature
×No heat of fusion
Crystalline Solid
Amorphous Solid

Sort each property by the type of solid it describes

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Vaporizing 10 Grams of Water

2 pts
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The heat of vaporization of water is 540 calories per gram. How much heat is needed to change 10 grams of water at 100°C entirely to water vapor at 100°C?

Answer = (1)

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Melting Ice vs. Vaporizing Water

1 pts
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Which requires more calories per gram: melting ice, or vaporizing water?

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Order the Steps: Ice at -20°C to Steam at 130°C

3 pts
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Please drag and drop the options to sort them

Arrange these steps in the order you would carry them out to change 1 gram of ice at -20°C into water vapor at 130°C.

Heat the water from 0°C to 100°C
Heat the ice from -20°C to 0°C
Melt the ice into water at 0°C
Vaporize the water into steam at 100°C
Heat the steam from 100°C to 130°C
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Fill In the Full Calculation: Ice at -20°C to Steam at 130°C

4 pts
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Given the specific heat of ice and of steam are both 0.5, find the total heat needed to change 1 gram of ice at -20°C to water vapor at 130°C, filling in each step:

  • Heat the ice from -20°C to 0°C (\(H = m \cdot c \cdot \Delta T\)): (1) cal
  • Melt the ice to water at 0°C (heat of fusion = 80 cal/g): (2) cal
  • Heat the water from 0°C to 100°C: (3) cal
  • Vaporize the water at 100°C (heat of vaporization = 540 cal/g): (4) cal
  • Heat the steam from 100°C to 130°C: (5) cal
  • Total heat needed: (6) cal
Please drag and drop the selected option in the right place or type it instead
540
100
15
10
80
745
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Why Warm Liquids Evaporate Faster

1 pts
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Missing

A warm liquid evaporates more quickly than a cool one because it has more ______ molecules capable of breaking free from the surface.

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Match the Term to What It Describes

3 pts
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To complete the line match
  1. Click on an item in the first group
  2. Click on an item in the second group
  3. To delete a match, double click on a line

Term

Heat of Vaporization
Boiling
Heat of Fusion

What Happens

Heat needed to break molecules free from fixed positions in a solid
Molecules break free from one another below the surface forming rising bubbles
Heat needed to break molecules completely free from one another in a liquid

Match each term on the left with what happens at the molecular level on the right.

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