The Section (Midpoint) Formula

Covers the midpoint formula and the general section formula for a point dividing a segment internally in a given ratio.

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Views #: 123
Questions #: 9
Time: 15 minutes
Pass Score: 80.0%
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The Midpoint's x-coordinate

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The midpoint formula for the segment from \(P_1(x_1, y_1)\) to \(P_2(x_2, y_2)\) gives the x-coordinate of the midpoint as:

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Find a Midpoint

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Find the midpoint of the segment joining (2, 4) and (8, 10). The midpoint is ((1), (2)).
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5
7
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The Congruent Triangles in the Derivation

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Missing
P₁(x₁, y₁) R(x, y₁) M(x, y) S(x₂, y₁) T(x₂, y) P₂(x₂, y₂)

Figure used to derive the midpoint formula

In the derivation of the midpoint formula, triangles P₁RM and MTP₂ are shown to be ______.

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The General Section Formula

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The general section formula for a point \(P(x, y)\) dividing the segment joining \(A(x_1, y_1)\) and \(B(x_2, y_2)\) internally in the ratio \(m:n\) gives \(x =\)

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Section Formula Reduces to the Midpoint Formula

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The section formula for internal division in the ratio m:n reduces to the ordinary midpoint formula when:
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Divide a Segment in a Given Ratio

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A point P divides the segment from A(0, 0) to B(10, 0) internally in the ratio 3:2. Find the x-coordinate of P.

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Order the Steps of the Derivation

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Arrange the steps used to derive the midpoint formula in the correct logical order.
Solve x − x1 = x2 − x and y − y1 = y2 − y
Note that triangles P1RM and MTP2 are congruent
Obtain x = (x1+x2)/2 and y = (y1+y2)/2
Set |P1R| = |MT| and |RM| = |TP2|
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The 1:1 Ratio Case

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In the section formula \(x = \dfrac{m\cdot x_2 + n\cdot x_1}{m+n}\), if \(m:n = 1:1\), this formula becomes:

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Assumptions in the Derivation

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In deriving the section formula \(x=\frac{mx_2+nx_1}{m+n},\ y=\frac{my_2+ny_1}{m+n}\), which assumption was made about the coordinates?

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Keywords
Year 10